故障繼電器跳脫特性的計算
Curve type | k | α | tr |
Standard inverse 1.3 | 0.06 | 0.02 | 1.3 |
Standard inverse 3.0 | 0.14 | 0.02 | 9.7 |
Very inverse | 13.5 | 1 | 43.2 |
Extremely inverse | 80 | 2 | 58.2 |
Long time inverse | 120 | 1 | 120 |
自行代入數值計算一下吧
以 SI - 1.3Sec 為例
TMS - 時限設定 (Time Setting)
k = 0.06
α = 0.05
I及Is簡單來說便是故障電流倍數
t(I)為跳脫時間
Standard Inverse 1.3Sec (SI)
TMS 0.2
2倍故障電流
答案 = 0.430 Sec
TMS 0.2
5倍故障電流
答案 = 0.183 Sec
TMS 0.2
10倍故障電流
答案 = 0.127 Sec
TMS 0.5
2倍故障電流
答案 = 2.149 Sec
TMS 0.5
5倍故障電流
答案 = 0.917 Sec
TMS 0.5
10倍故障電流
答案 = 0.637 Sec
TMS 1.0
2倍故障電流
答案 = 4.298 Sec
TMS 1.0
5倍故障電流
答案 = 1.834 Sec
TMS 1.0
10倍故障電流
答案 = 1.273 Sec
Standard Inverse 3Sec
TMS 0.2
2倍故障電流
答案 = 1.003 Sec
TMS 0.2
5倍故障電流
答案 = 0.428 Sec
TMS 0.2
10倍故障電流
答案 = 0.297 Sec
TMS 0.5
2倍故障電流
答案 = 5.105 Sec
TMS 0.5
5倍故障電流
答案 = 2.140 Sec
TMS 0.5
10倍故障電流
答案 = 1.485 Sec
TMS 1.0
2倍故障電流
答案 = 10.029 Sec
TMS 1.0
5倍故障電流
答案 = 4.280 Sec
TMS 1.0
10倍故障電流
答案 = 2.971 Sec
Standard Inverse 又名為Normal Inverse (NI)
Very Inverse 13.5Sec (VI)
TMS 0.2
2倍故障電流
答案 = 1.350 Sec
TMS 0.2
5倍故障電流
答案 = 0.338 Sec
TMS 0.2
10倍故障電流
答案 = 0.150 Sec
TMS 0.5
2倍故障電流
答案 = 6.750 Sec
TMS 0.5
5倍故障電流
答案 = 1.688 Sec
TMS 0.5
10倍故障電流
答案 = 0.750 Sec
TMS 1.0
2倍故障電流
答案 = 13.500 Sec
TMS 1.0
5倍故障電流
答案 = 3.375 Sec
TMS 1.0
10倍故障電流
答案 = 1.500 Sec
Extremely Inverse 80Sec (EI)
TMS 0.2
2倍故障電流
答案 = 2.667 Sec
TMS 0.2
5倍故障電流
答案 = 0.333 Sec
TMS 0.2
10倍故障電流
答案 = 0.081 Sec
TMS 0.5
2倍故障電流
答案 = 13.333 Sec
TMS 0.5
5倍故障電流
答案 = 1.667 Sec
TMS 0.5
10倍故障電流
答案 = 0.404 Sec
TMS 1.0
2倍故障電流
答案 = 26.667 Sec
TMS 1.0
5倍故障電流
答案 = 3.333 Sec
TMS 1.0
10倍故障電流
答案 = 0.808 Sec
Long Time Inverse 120Sec
TMS 0.2
2倍故障電流
答案 = 12.000 Sec
TMS 0.2
5倍故障電流
答案 = 3.000 Sec
TMS 0.2
10倍故障電流
答案 = 1.333 Sec
TMS 0.5
2倍故障電流
答案 = 60.000 Sec
TMS 0.5
5倍故障電流
答案 = 15.000 Sec
TMS 0.5
10倍故障電流
答案 = 6.667 Sec
TMS 1.0
2倍故障電流
答案 = 120.000 Sec
TMS 1.0
5倍故障電流
答案 = 30.000 Sec
TMS 1.0
10倍故障電流
答案 = 13.333 Sec
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同路英雄 http://elvissharing.blogspot.com/ www.dinhaylo.com https://e-m-life.blogspot.com/ |
請問我的保護繼電器平常用EI curve, 若果我進行次級注電測試用VI curve測試(測試結果於合格範圍), 測試能否証明保護繼電器EI curve功能正常.
回覆刪除大多數情況電子式繼電器,只有準確與不工作兩個可能,當然有少數例外,默認的是使用那條特性曲線,便用那個來測試,被受質疑的話,你又如果說明它的準確性?
回覆刪除